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(1) 解方程: $2 x^2+4 x-1=0$;
(2) 解不等式组 $\left\{\begin{array}{l}5 x-2>3(x+1) \\ \frac{1}{2} x-1 \leqslant 7-\frac{3}{2} x\end{array}\right.$.
                        
不再提醒