• 试题 ID 4251


(1) 解方程: $2 x^2+4 x-1=0$;
(2) 解不等式组 $\left\{\begin{array}{l}5 x-2>3(x+1) \\ \frac{1}{2} x-1 \leqslant 7-\frac{3}{2} x\end{array}\right.$.
A
B
C
D
E
F
答案:

答案与解析仅限VIP可见

解析:

答案与解析仅限VIP可见