查看原题
$A=\left\{x \mid x^2-5 x+6 \leq 0\right\}, B=\{x \mid-1 \leq x < 3\}$, 则 $A \cap B=$
A. $\{x \mid-1 \leq x < 3\}$     B. $\{x \mid-1 \leq x \leq 3\}$     C. $\{x \mid 2 \leq x < 3\}$     D. $\{x \mid 2 \leq x \leq 3\}$         
不再提醒