• 试题 ID 12528


$A=\left\{x \mid x^2-5 x+6 \leq 0\right\}, B=\{x \mid-1 \leq x < 3\}$, 则 $A \cap B=$
A $\{x \mid-1 \leq x < 3\}$
B $\{x \mid-1 \leq x \leq 3\}$
C $\{x \mid 2 \leq x < 3\}$
D $\{x \mid 2 \leq x \leq 3\}$
E
F
答案:

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解析:

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