已知 $P(A) P(A B) \neq 0$, 则正确的是
$\text{A.}$ $P(B C \mid A)=P(B) P(C \mid A B)$
$\text{B.}$ $P(B \mid A)=P(A)-P(\bar{B} \mid A)$
$\text{C.}$ $P(B C \mid A)=1-P(\bar{B} \bar{C} \mid A)$
$\text{D.}$ $P(B \cup C \mid A)=P(B \mid A)+P(C \mid A)-P(B C \mid A)$