$\left(\begin{array}{lll}0 & 1 & 0 \\ 1 & 0 & 0 \\ 0 & 0 & 1\end{array}\right)^{2017}\left(\begin{array}{lll}1 & 2 & 3 \\ 4 & 5 & 6 \\ 7 & 8 & 9\end{array}\right)\left(\begin{array}{lll}0 & 0 & 1 \\ 0 & 1 & 0 \\ 1 & 0 & 0\end{array}\right)^{2018}=$
【答案】 $\left(\begin{array}{lll}4 & 5 & 6 \\ 1 & 2 & 3 \\ 7 & 8 & 9\end{array}\right)$

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