• 试题 ID 32606


$\frac{1}{1+\sqrt{3}}+\frac{1}{\sqrt{2}+2}+\frac{1}{\sqrt{3}+\sqrt{5}}+. . .+\frac{1}{\sqrt{97}+\sqrt{99}}+\frac{1}{\sqrt{98}+10}=$

A 9
B $\frac{9}{2}$
C $\frac{9+3 \sqrt{11}-\sqrt{2}}{2}$
D $\frac{7+3 \sqrt{11}}{2}$
E
F
答案:

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解析:

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