• 试题 ID 20099


解方程组:
(1) $\left\{\begin{array}{l}4 x+y=6 \\ 6 x+y=8\end{array}\right.$
(2) $\left\{\begin{array}{l}3(x+y)-4(x-y)=4 \\ \frac{x+y}{2}+\frac{x-y}{6}=1\end{array}\right.$
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答案:

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解析:

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