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已知$\sin^2(\pi-\theta)=\dfrac{\sqrt{3}}{2}\cos\left(\dfrac{3\pi}{2}+\theta\right)$,且$0 < |\theta| < \dfrac{\pi}{2}$,则$\theta$等于（　　）.
A. $-\dfrac{\pi}{6}$     B. $-\dfrac{\pi}{3}$     C. $\dfrac{\pi}{6}$     D. $\dfrac{\pi}{3}$         
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