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设 $z=\sin \left(x+y^2\right)$ ,则 $\dfrac{\partial^2 z}{\partial x^2}=$.
A. $-\sin \left(x+y^2\right)$     B. $-\cos \left(x+y^2\right)$     C. $\sin \left(x+y^2\right)$     D. $\cos \left(x+y^2\right)$         
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