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设函数 $f(u)$ 连续, 区域 $D=\left\{(x, y) \mid x^2+y^2 \leq 2 y\right\}$, 则 $\iint_D f(x y) \mathrm{d} x \mathrm{~d} y$ 等于
A. $\int_{-1}^1 \mathrm{~d} x \int_{-\sqrt{1-x^2}}^{\sqrt{1-x^2}} f(x y) \mathrm{d} y$     B. $2 \int_0^2 \mathrm{~d} y \int_0^{\sqrt{2 y-y^2}} f(x y) \mathrm{d} x$.     C. $\int_0^\pi \mathrm{d} \theta \int_0^{2 \sin \theta} f\left(r^2 \sin \theta \cos \theta\right) \mathrm{d} r$.     D. $\int_0^\pi \mathrm{d} \theta \int_0^{2 \sin \theta} f\left(r^2 \sin \theta \cos \theta\right) r \mathrm{~d} r$.         
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