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设 $A, B, C$ 为随机事件,若 $P(C)>0$ ,且

$$
P(A \cup B \mid C)=P(A \mid C)+P(B \mid C) .
$$
则下列结论正确的是
A. $P(A \cup B \mid \bar{C})=P(A \mid \bar{C})+P(B \mid \bar{C})$ ;     B. $P(A \cup B)=P(A \mid C)+P(B \mid C)$ ;     C. $P(C)=P(A) P(C \mid A)+P(B) P(C \mid B)$ ;     D. $P(C(A \cup B))=P(A C)+P(B C)$ .         
不再提醒