设
$$
\boldsymbol{A}=\left(\begin{array}{llll}
a_{11} & a_{12} & a_{13} & a_{14} \\
a_{21} & a_{22} & a_{23} & a_{24} \\
a_{31} & a_{32} & a_{33} & a_{34} \\
a_{41} & a_{42} & a_{43} & a_{44}
\end{array}\right), \boldsymbol{B}=\left(\begin{array}{llll}
a_{14} & a_{13} & a_{12} & a_{11} \\
a_{24} & a_{23} & a_{22} & a_{21} \\
a_{34} & a_{33} & a_{32} & a_{31} \\
a_{44} & a_{43} & a_{42} & a_{41}
\end{array}\right), \boldsymbol{P}_1=\left(\begin{array}{cccc}
0 & 0 & 0 & 1 \\
0 & 1 & 0 & 0 \\
0 & 0 & 1 & 0 \\
1 & 0 & 0 & 0
\end{array}\right),
$$
$\boldsymbol{P}_2=\left(\begin{array}{llll}1 & 0 & 0 & 0 \\ 0 & 0 & 1 & 0 \\ 0 & 1 & 0 & 0 \\ 0 & 0 & 0 & 1\end{array}\right)$ ，其中 $\boldsymbol{A}$ 可逆，则 $\boldsymbol{B}^{-1}$ 等于
A. $\boldsymbol{A}^{-1} \boldsymbol{P}_1 \boldsymbol{P}_2$ ．
B. $\boldsymbol{P}_1 \boldsymbol{A}^{-1} \boldsymbol{P}_2$ ．
C. $\boldsymbol{P}_1 \boldsymbol{P}_2 \boldsymbol{A}^{-1}$ ．
D. $\boldsymbol{P}_2 \boldsymbol{A}^{-1} \boldsymbol{P}_1$ ．