查看原题
已知 $P(A) P(A B) \neq 0$, 则正确的是
A. $P(B C \mid A)=P(B) P(C \mid A B)$     B. $P(B \mid A)=P(A)-P(\bar{B} \mid A)$     C. $P(B C \mid A)=1-P(\bar{B} \bar{C} \mid A)$     D. $P(B \cup C \mid A)=P(B \mid A)+P(C \mid A)-P(B C \mid A)$         
不再提醒