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设 $f(x)=\left\{\begin{array}{ll}1, & |x| \leq 1 \\ 0, & |x|>1\end{array}\right.$ ,则 $f\{f[f(x)]\}$ 等于
A. 0     B. 1     C. $\left\{\begin{array}{l}1,|x| \leq 1 \\ 0,|x|>1\end{array}\right.$     D. $\begin{cases}0, & |x| \leq 1 \\ 1, & |x|>1\end{cases}$         
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