设 $f(x, y)$ 为连续函数，则 $\int_0^{\frac{\pi}{4}} \mathrm{~d} \theta \int_0^1 f(r \cos \theta, r \sin \theta) r \mathrm{~d} r$ 等于
A
$\int_0^{\frac{\sqrt{2}}{2}} \mathrm{~d} x \int_x^{\sqrt{1-x^2}} f(x, y) \mathrm{d} y$
B
$\int_0^{\frac{\sqrt{2}}{2}} \mathrm{~d} x \int_0^{\sqrt{1-x^2}} f(x, y) \mathrm{d} y$
C
$\int_0^{\frac{\sqrt{2}}{2}} \mathrm{~d} y \int_y^{\sqrt{1-y^2}} f(x, y) \mathrm{d} x$
D
$\int_0^{\frac{\sqrt{2}}{2}} \mathrm{~d} y \int_0^{\sqrt{1-y^2}} f(x, y) \mathrm{d} x$
E
F